| ⇦ |
| ⇨ |
The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is
Options
(a) π
(b) 0.707π
(c) zero
(d) 0.5π
Correct Answer:
0.5π
Explanation:
Let y = A sin ωt
vinst = dy/ dt = Aω cos ωt
vinst = Aω² sin (ωt + π/2)
Acceleration = – Aω² sin ωt = Aω²sin (π + ωt)
ɸ = π/2 = 0.5 π.
Related Questions: - A thin wire of length L and mass M is bent to form a semicircle.
- A body starts from rest, what is the ratio of the distance travelled by the body
- Imagine a new planet having the same density as that of earth but it is 3 times bigger
- An iron rod of volume 10⁻⁴ m³ and relative permeability 1000 is placed inside a long
- If two slits in Young’s experiment are 0.4 mm apart and fringe width on a screen
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A thin wire of length L and mass M is bent to form a semicircle.
- A body starts from rest, what is the ratio of the distance travelled by the body
- Imagine a new planet having the same density as that of earth but it is 3 times bigger
- An iron rod of volume 10⁻⁴ m³ and relative permeability 1000 is placed inside a long
- If two slits in Young’s experiment are 0.4 mm apart and fringe width on a screen
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply