The phase difference between the instantaneous velocity and acceleration of a particle

⇦

⇨

The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is

Options

(a) π
(b) 0.707π
(c) zero
(d) 0.5π

Correct Answer:

0.5π

Explanation:

Let y = A sin ωt
v_inst = dy/ dt = Aω cos ωt
v_inst = Aω² sin (ωt + π/2)
Acceleration = – Aω² sin ωt = Aω²sin (π + ωt)
ɸ = π/2 = 0.5 π.

Related Questions:

1. The flux linked with a circuit is given by φ=t³+3t-7. The graph between time
2. A 1 kg particle strikes a wall with velocity 1 m/s at an angle 30° and reflects
3. The polarising angle of glass is 57⁰. A ray of light which is incident at this angle
4. In a compound microscope, the focal length of the objective is 2.5 cm and of eye lens
5. Consider the following two statements about Kirchhoff’s law

Topics: Oscillations (58)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends