| ⇦ | 
| ⇨ |
The phase difference between the instantaneous velocity and acceleration of a particle executing simple harmonic motion is
Options
(a) π
(b) 0.707π
(c) zero
(d) 0.5π
Correct Answer:
0.5π
Explanation:
Let y = A sin ωt
vinst = dy/ dt = Aω cos ωt
vinst = Aω² sin (ωt + π/2)
Acceleration = – Aω² sin ωt = Aω²sin (π + ωt)
ɸ = π/2 = 0.5 π.
Related Questions: - A body covers 200 cm in the first 2 seconds and 220 cm in the next 4 seconds.
- Length of a conductor is 50 cm radius of cross section 0.1 cm and resistivity
- A particle of mass m oscillates along x-axis according to equation x = a sin ?t
- In a common emitter (CE) amplifier having a voltage gain G, the transistor
- A national roadway bridge over a canal is in the form of an arc of a circle of radius
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body covers 200 cm in the first 2 seconds and 220 cm in the next 4 seconds.
- Length of a conductor is 50 cm radius of cross section 0.1 cm and resistivity
- A particle of mass m oscillates along x-axis according to equation x = a sin ?t
- In a common emitter (CE) amplifier having a voltage gain G, the transistor
- A national roadway bridge over a canal is in the form of an arc of a circle of radius
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply