| ⇦ | 
| ⇨ |
In a compound microscope, the focal length of the objective is 2.5 cm and of eye lens is 5 cm. If an object is placed at 3.75 cm before the objective and the image is formed at the least distance of distinct vision, then the distance between two lenses will be
Options
(a) 11.67 cm
(b) 12 cm
(c) 12.75 cm
(d) 13 cm
Correct Answer:
11.67 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - What will be the ratio of the distance moved by a freely falling body from rest in 4th
- Avalanche breakdown is due to
- If energy(E), velocity(V) and time(T) are chosen as fundamental quantities,
- The dimensions of universal gas constant are
- If the unit of force and length are doubled, then unit of energy will be
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What will be the ratio of the distance moved by a freely falling body from rest in 4th
- Avalanche breakdown is due to
- If energy(E), velocity(V) and time(T) are chosen as fundamental quantities,
- The dimensions of universal gas constant are
- If the unit of force and length are doubled, then unit of energy will be
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply