| ⇦ | 
| ⇨ |
The depth at which the effective value of acceleration due to gravity is g/4 is (R=Radius of earth)
Options
(a) R
(b) 3R/4
(c) R/2
(d) R/4
Correct Answer:
3R/4
Explanation:
The effect of depth of acceleration due to gravity is g’=g(1-d/R)
Given, g’=g/4
g/4=g(1-d/R)
(g/4)/g=(1-d/R)
1/4=1-d/R ⇒d/R=1-1/4 ⇒3/4
d=3R/4
Related Questions: - A person cannot see the objects clearly placed at a distance more than 40 cm
- Laser beams are used to measure long distance because
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- When an object is placed 40cm from a diverging lens, its virtual image is formed 20 cm
- The innermost orbit of hydrogen atom has a diameter 1.06Å. The diameter of tenth
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A person cannot see the objects clearly placed at a distance more than 40 cm
- Laser beams are used to measure long distance because
- The binding energy of deutron is 2.2 MeV and that of ₂⁴He is 28 MeV.
- When an object is placed 40cm from a diverging lens, its virtual image is formed 20 cm
- The innermost orbit of hydrogen atom has a diameter 1.06Å. The diameter of tenth
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply