| ⇦ | 
| ⇨ |
The depth at which the effective value of acceleration due to gravity is g/4 is (R=Radius of earth)
Options
(a) R
(b) 3R/4
(c) R/2
(d) R/4
Correct Answer:
3R/4
Explanation:
The effect of depth of acceleration due to gravity is g’=g(1-d/R)
Given, g’=g/4
g/4=g(1-d/R)
(g/4)/g=(1-d/R)
1/4=1-d/R ⇒d/R=1-1/4 ⇒3/4
d=3R/4
Related Questions: - A body is thrown vertically up with a velocity u.It passes three points A,B and C
- A beam of light of wavelength 590 nm is focussed by a converging lens of diameter
- When 1 kg of ice at 0⁰C melts to water at 0⁰C, the resulting change in its entropy
- The electirc field in a certain region is acting radially outward and is given by E=Ar.
- Which of the following, is a vector quantity?
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body is thrown vertically up with a velocity u.It passes three points A,B and C
- A beam of light of wavelength 590 nm is focussed by a converging lens of diameter
- When 1 kg of ice at 0⁰C melts to water at 0⁰C, the resulting change in its entropy
- The electirc field in a certain region is acting radially outward and is given by E=Ar.
- Which of the following, is a vector quantity?
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply