| ⇦ | 
| ⇨ |
The height at which the weight of a body becomes 1/16 th, its weight on the surface of earth (radius R), is
Options
(a) 5 R
(b) 15 R
(c) 3 R
(d) 4 R
Correct Answer:
3 R
Explanation:
Let at h height, the weight of a body becomes 1/16th of its weight on the surface.
Wh = 16 Ws g’ = GM/(Re+h)²
Similarly, g = GM/Re²
Now, g’/g = Re²/(Re+h)²
⇒ g’=g(1+h/R)⁻²
⇒ Wh = 16 Ws
⇒ g’ = g/16 g’
= 16g(1+h/R)⁻² 1/16
= (1+h/R)⁻²
⇒ 4 = 1+h/R
⇒ h = 3 R
Related Questions: - What is the energy released by fission of 1 g of U²³⁵?
- A body has 80 microcoulomb of charge. Number of additional electrons in it will be
- The self induced e.m.f. in a 0.1 H coil when the current in it is changing
- A stone tied to the end of a string of 1 m long is whirled in a horizontal circle
- When an α-particle of mass m moving with velocity ν bombards on a heavy nucleus
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- What is the energy released by fission of 1 g of U²³⁵?
- A body has 80 microcoulomb of charge. Number of additional electrons in it will be
- The self induced e.m.f. in a 0.1 H coil when the current in it is changing
- A stone tied to the end of a string of 1 m long is whirled in a horizontal circle
- When an α-particle of mass m moving with velocity ν bombards on a heavy nucleus
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply