| ⇦ |
| ⇨ |
The damping force on an oscillator is directly proportional to the velocity. The units of the constant of proportionality are:
Options
(a) kgms⁻¹
(b) kgms⁻²
(c) kgs⁻¹
(d) kgs
Correct Answer:
kgs⁻¹
Explanation:
F ∞ v ⇒ F = kv
k = F / v ⇒ [k] = [kgms⁻²] / [ms⁻¹]
= kgs⁻¹
Related Questions: - Two springs with spring constants K₁=1500 N/m and K₂=3000 N/m
- If v is the speed of sound in air, then the shortest length of the closed pipe
- A satellite is launched into a circular orbit of radius R around earth while
- A body takes 5 minute for cooling from 50⁰C to 40⁰C. Its temperature
- A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two springs with spring constants K₁=1500 N/m and K₂=3000 N/m
- If v is the speed of sound in air, then the shortest length of the closed pipe
- A satellite is launched into a circular orbit of radius R around earth while
- A body takes 5 minute for cooling from 50⁰C to 40⁰C. Its temperature
- A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply