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The period of oscillation of a mass M suspended from a spring of negligible mass is T. If along with it another mass M is also suspended, the period of oscillation will now be
Options
(a) T
(b) T / √2
(c) 2T
(d) √2T
Correct Answer:
√2T
Explanation:
T = 2π √(m / K)
T₁ / T₂ = √(M₁ /M₂)
T₂ = T₁√(M₂ / M₁) = T₁ √(2M / M)
T₂ = T₁ √2 = √2 T (where T₁ = T)
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two bodies of masses m and 4 m are moving with equal K.E. The ratio of their linear
- A flywheel rotating about a fixed axis has a kinetic energy of 360 J when
- A piece of marble is projected from the earth’s surface with velocity of 50 m/s
- The near point and far point of a person are 40 cm and 250 cm, respectively.
- The value of n so that vectors 2i+3j-2k, 5i+nj+k and -i+2j+3k may be coplanar,will be
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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