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The period of oscillation of a mass M suspended from a spring of negligible mass is T. If along with it another mass M is also suspended, the period of oscillation will now be
Options
(a) T
(b) T / √2
(c) 2T
(d) √2T
Correct Answer:
√2T
Explanation:
T = 2π √(m / K)
T₁ / T₂ = √(M₁ /M₂)
T₂ = T₁√(M₂ / M₁) = T₁ √(2M / M)
T₂ = T₁ √2 = √2 T (where T₁ = T)
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A satellite of mass m revolves around the earth of radius R at a height x from
- what is the de-Broglie wavelength of the electron accelerated through a potential
- A block of mass 5 kg is moving horizontally at a speed of 1.5 m/s. A perpendicular force
- A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 secs
- The wave described by y = 0.25 sin (10 2πx – 2πt), where x and y are in meters
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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