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The period of oscillation of a mass M suspended from a spring of negligible mass is T. If along with it another mass M is also suspended, the period of oscillation will now be
Options
(a) T
(b) T / √2
(c) 2T
(d) √2T
Correct Answer:
√2T
Explanation:
T = 2π √(m / K)
T₁ / T₂ = √(M₁ /M₂)
T₂ = T₁√(M₂ / M₁) = T₁ √(2M / M)
T₂ = T₁ √2 = √2 T (where T₁ = T)
Related Questions: - A bar magnet of magnetic moment M is placed at right angles to a magnetic
- The workdone in turning a magnet of magnetic moment M by an angle of 90⁰ from the magnetic
- Rutherford’s α-scattering experiment concludes that
- A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A bar magnet of magnetic moment M is placed at right angles to a magnetic
- The workdone in turning a magnet of magnetic moment M by an angle of 90⁰ from the magnetic
- Rutherford’s α-scattering experiment concludes that
- A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
- A cylindrical tank is filled with water to a level of 3m. A hole is opened at a height
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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