| ⇦ |
| ⇨ |
The period of oscillation of a mass M suspended from a spring of negligible mass is T. If along with it another mass M is also suspended, the period of oscillation will now be
Options
(a) T
(b) T / √2
(c) 2T
(d) √2T
Correct Answer:
√2T
Explanation:
T = 2π √(m / K)
T₁ / T₂ = √(M₁ /M₂)
T₂ = T₁√(M₂ / M₁) = T₁ √(2M / M)
T₂ = T₁ √2 = √2 T (where T₁ = T)
Related Questions: - Two spheres A and B of masses m and m respectively collide. A is at rest initially
- The equations of motion of a projectile are given by x=36 t metre and 2y=96t-9.8t²
- The limiting angle of incidence for an optical ray that can be transmitted
- At absolute temperature, the kinetic energy of the molecules
- An electron in hydrogen atom makes a transition n₁ → n₂
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two spheres A and B of masses m and m respectively collide. A is at rest initially
- The equations of motion of a projectile are given by x=36 t metre and 2y=96t-9.8t²
- The limiting angle of incidence for an optical ray that can be transmitted
- At absolute temperature, the kinetic energy of the molecules
- An electron in hydrogen atom makes a transition n₁ → n₂
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply