| ⇦ |
| ⇨ |
The acceleration due to gravity at a place is π² m/sec². Then the time period of a simple pendulum of length one metre is
Options
(a) 2/π sec
(b) 2π sec
(c) 2 sec
(d) π sec
Correct Answer:
2 sec
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The transverse nature of electromagnetic waves is proved by which of the following?
- Two wires of equal length and equal diameter and having resistivities ρ₁ and ρ₂
- During production of cathode ray
- If a body is rolling on the surface, its total energy will be
- If two bodies are projected at 30⁰ and 60⁰ respectively with the same velocity, then
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The transverse nature of electromagnetic waves is proved by which of the following?
- Two wires of equal length and equal diameter and having resistivities ρ₁ and ρ₂
- During production of cathode ray
- If a body is rolling on the surface, its total energy will be
- If two bodies are projected at 30⁰ and 60⁰ respectively with the same velocity, then
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply