| ⇦ | 
| ⇨ |
If h is Planck’s constant, the momentum of a photon of wavelength 0.01 Å is
Options
(a) 10⁻² h
(b) h
(c) 10² h
(d) 10¹² h
Correct Answer:
10¹² h
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle under the action of a constant force moves from rest upto 20 seconds
- A charged particle with a velocity 2×10³ ms⁻¹ passes undeflected through electric field
- The equation of state for 5 g of oxygen at a pressure P and temperature T,
- The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP
- Number of electrons in one mC charge, given e=1.6×10⁻¹⁹ C, will be
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle under the action of a constant force moves from rest upto 20 seconds
- A charged particle with a velocity 2×10³ ms⁻¹ passes undeflected through electric field
- The equation of state for 5 g of oxygen at a pressure P and temperature T,
- The drive shaft of an automobile rotates at 3600 rpm and transmits 80 HP
- Number of electrons in one mC charge, given e=1.6×10⁻¹⁹ C, will be
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
momentum is given by p=h/lambda
As h is constant so p is inversely proportional to lambda. The value of lambda is 0.01 angstrom I.e, 1×102 Angstrom. and angstrom is equals to 10 raised to the power 10. so the equation becomes p=1/1×102×1010. p=1/1×1012
p=10 raised to the power -12. So the answer is ×10-12.