| ⇦ |
| ⇨ |
A transistor is working in common emitter mode. Its amplification factor is 80. If the base current is 250 µA, what is the current at the collector?
Options
(a) 250 µA
(b) 250 x 80 µA
(c) 80 µA
(d) 200 x 80 µA
Correct Answer:
250 x 80 µA
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Light of wavelength λ is incident on slit of width d. The resulting diffraction
- A particle moving in a straight line with uniform acceleration is observed
- Two waves of same amplitude superpose. The resultant intensity is I₁
- The electric field in a certain region is acting radially outward and is given by E=Ar.
- The phase difference between two points seperated by 0.8 m in a wave of frequency
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Light of wavelength λ is incident on slit of width d. The resulting diffraction
- A particle moving in a straight line with uniform acceleration is observed
- Two waves of same amplitude superpose. The resultant intensity is I₁
- The electric field in a certain region is acting radially outward and is given by E=Ar.
- The phase difference between two points seperated by 0.8 m in a wave of frequency
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply