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Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
Options
(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero
Correct Answer:
Mv newton
Explanation:
F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- With the decrease of current in the primary coil from 2 amperes to zero value
- One mole of an ideal gas at an initial temperature of T K, does 6R joule of work
- The angle between the two vectors A = 3i+4j+5k and B = 3i+4j-5k will be
- When temperature of an ideal gas is increased from 27⁰C to 227⁰C,
- A current is flowing through resistance. A potential difference of 120 V
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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