Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary

⇦

⇨

Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:

Options

(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero

Correct Answer:

Mv newton

Explanation:

F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.

Related Questions:

1. Two resistances 3Ω and 6Ω are connected in parallel
2. A wire mesh consisting of very small squares is viewed at a distance
3. A spherical planet has a mass Mp and diameter Dp. A particle of mass
4. The acceleration of an electron in an electric field of magnitude 50 V/cm,
5. A transistor is working in common emitter mode. Its amplification factor is 80

Topics: Laws of Motion (103)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends