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Sand is being dropped on a conveyor belt at the rate of M kg/s. The force necessary to keep the belt moving with a constant velocity of v m/s will be:
Options
(a) Mv newton
(b) 2 Mv newton
(c) Mv/2 newton
(d) zero
Correct Answer:
Mv newton
Explanation:
F = d(Mv) / dt = M . dv / dt + v . dM / dt
v is constant,
F = vdM / dt But dM / dt = Mkg / s
F = vM newton.
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- Masses of three wires of copper are in the ratio of 1:3:5 and their lengths
- A force of 10N is applied on a body for 3 sec and the corresponding displacement 6 m.
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The conducting loop in the form of a circle is placed in a uniform magneitc field
- Masses of three wires of copper are in the ratio of 1:3:5 and their lengths
- A force of 10N is applied on a body for 3 sec and the corresponding displacement 6 m.
- A change of 0.04 V takes place between the base and the emitter when an input
- Sound waves travel at 350m/s through a warm air and at 3500 m/s through brass
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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