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A force of 10N is applied on a body for 3 sec and the corresponding displacement 6 m. The power of the source is
Options
(a) 20 W
(b) 25 W
(c) 40 W
(d) 50 W
Correct Answer:
20 W
Explanation:
Velocity, v = displacement / time = 6/3 = 2 m/s
.·. Power, P = Fv = 10 × 2 = 20 W
Related Questions: - The dimensions of Planck’s constant is same as that of
- Which of the following is a vector quantity?
- A dynamo converts
- A spring of spring constant 5 x 10³ N/m is stretched initially by 5 cm
- A common emitter amplifier is designed with n-p-n transistor (α=0.99).
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The dimensions of Planck’s constant is same as that of
- Which of the following is a vector quantity?
- A dynamo converts
- A spring of spring constant 5 x 10³ N/m is stretched initially by 5 cm
- A common emitter amplifier is designed with n-p-n transistor (α=0.99).
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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