⇦ | ⇨ |
In the series resonance the value of impedence is 3 Ω and the resistance is 4Ω, then the value of power factor of the circuit is
Options
(a) (4/3)
(b) (3/4)
(c) zero
(d) infinity
Correct Answer:
(4/3)
Explanation:
Power factor cos ɸ = Resistance / Impedance = 4 / 3.
Related Questions: - In the Young’s double slit experiment, a point P on the central bright fringe
- A particle moves along the x-axis from x=0 to x=5 m under the influence of a force
- A galvanometer has a coil of resistance 100 ohm and gives a full-scale deflection
- When germanium is doped with phosphorus what type of semiconductor is produced?
- A circuit contains an ammeter, a battery of 30 V and a resistance 40.8 ohm
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the Young’s double slit experiment, a point P on the central bright fringe
- A particle moves along the x-axis from x=0 to x=5 m under the influence of a force
- A galvanometer has a coil of resistance 100 ohm and gives a full-scale deflection
- When germanium is doped with phosphorus what type of semiconductor is produced?
- A circuit contains an ammeter, a battery of 30 V and a resistance 40.8 ohm
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply