| ⇦ |
| ⇨ |
If the length of a closed organ pipe is 1.5 m and velocity of sound is 330 m/s, then the frequency for the second note is
Options
(a) 220 Hz
(b) 165 Hz
(c) 110 Hz
(d) 55 Hz
Correct Answer:
165 Hz
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Unit of electrical conductivity is
- For principal quantum number n=3, the possible values of orbital quantum number
- What is the value of incidence L for which the current is maximum in a series LCR
- If liquid level falls in a capillary then radius of capillary will be
- The total kinetic energy of a body of mass 10 kg and radius 0.5 m moving with a velocity
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Unit of electrical conductivity is
- For principal quantum number n=3, the possible values of orbital quantum number
- What is the value of incidence L for which the current is maximum in a series LCR
- If liquid level falls in a capillary then radius of capillary will be
- The total kinetic energy of a body of mass 10 kg and radius 0.5 m moving with a velocity
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply