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₉₂U²³⁵ undergoes successive disintegrations with the end product of ₈₂P²⁰³. The number of α and β-particles emitted are
Options
(a) α=8,β=6
(b) α=3,β=3
(c) α=6,β=4
(d) α=6,β=0
Correct Answer:
α=8,β=6
Explanation:
₉₂U²³⁵ → end product ₈₂P²°³ α and β emitted.
ΔA = 235 – 203 = 32
Therefore, 8 alpha particles are emitted. The charge should be 92 – 16 = 76.
But as the final charge is 82, six β⁻ particles had been emitted to make up the final atomic number Z = 82.
.·. 8 alpha particles and six β⁻ have been emitted.
Related Questions: - The half life of a radioactive isotope ‘X’ is 20 years. It decays to another element Y
- Two concentric coils each of radius equal to 2π cm are placed at right angles
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The half life of a radioactive isotope ‘X’ is 20 years. It decays to another element Y
- Two concentric coils each of radius equal to 2π cm are placed at right angles
- The temperature coefficient of the resistance of a wire is 0.00125 per ⁰C.
- In the given figure, a diode D is connected to an external resistance R=100 Ω
- Function of a rectifier is
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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