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If rope of lift breaks suddenly, the tension exerted by the surface of the lift (a = Acceleration of lift) is
Options
(a) mg
(b) m(g+a)
(c) zero
(d) m(g-a)
Correct Answer:
zero
Explanation:
If the rope suddenly breaks, acceleration = g
So substituting in formula, tension T=m(g−a)=0
Related Questions: - A uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support.
- A 36 Ω galvanometer is shunted by resistance of 4 Ω. The percentage of the total current
- IF A⃗ and B⃗ are two vectors and θ is the angle between them
- In the Bohr’s model of hydrogen atom, the ratio of the kinetic energy to the total
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support.
- A 36 Ω galvanometer is shunted by resistance of 4 Ω. The percentage of the total current
- IF A⃗ and B⃗ are two vectors and θ is the angle between them
- In the Bohr’s model of hydrogen atom, the ratio of the kinetic energy to the total
- A cell can be balanced against 110 cm and 100 cm of potentiometer wire, respectively
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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