| ⇦ | 
| ⇨ |
The minimum velocity (in ms⁻¹) with which a car driver must traverse a flat curve of radius 150 m and coefficient of friction 0.6 to avoid skidding is
Options
(a) 60 ms⁻¹
(b) 30 ms⁻¹
(c) 15 ms⁻¹
(d) 25 ms⁻¹
Correct Answer:
30 ms⁻¹
Explanation:
Using the relation,
or v² = μrg
= 0.6 x 150 x 10
v = 30 ms⁻¹.
Related Questions: - Electric field intensity at a point in between two parallel sheets due to like
- The speed of light in media M₁ and M₂ are 1.5×10⁸ ms⁻¹ and 2×10⁸ ms⁻¹ respectively.
- Pure Si at 500 K has equal number of electron (nₑ) and hole (nₕ) concentrations
- An electron moves on a straight line path XY as shown. The abcd is a coil adjacent
- A 6 volt battery is connected to the terminals of a three metre long wire of uniform
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Electric field intensity at a point in between two parallel sheets due to like
- The speed of light in media M₁ and M₂ are 1.5×10⁸ ms⁻¹ and 2×10⁸ ms⁻¹ respectively.
- Pure Si at 500 K has equal number of electron (nₑ) and hole (nₕ) concentrations
- An electron moves on a straight line path XY as shown. The abcd is a coil adjacent
- A 6 volt battery is connected to the terminals of a three metre long wire of uniform
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply