| ⇦ | 
| ⇨ |
If a body is rolling on the surface, its total energy will be
Options
(a)(1/2) mv² – (Gm₁m₂/R)
(b) (1/2) mv² + (1/2) Iω²
(c) (1/2) mv² – (1/2) mR²ω²
(d) None
Correct Answer:
(1/2) mv² + (1/2) Iω²
Explanation:
Total energy = P.E. + K.E. of (linear motion + Rotation)
= 0 + (1/2) mv² + (1/2) Iω²
Total energy = (1/2) mv² + (1/2) Iω².
Related Questions: - Which of the two have same dimensions?
- When alpha particles captures and electron, then it becomes a
- The phase difference between the flux linked with a coil rotating in a uniform
- The effective length of magnet is 31.4 cm and its pole strength is 0.8Am.
- The particle executing simple harmonic motion has a kinetic energy K₀cos²ωt.
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the two have same dimensions?
- When alpha particles captures and electron, then it becomes a
- The phase difference between the flux linked with a coil rotating in a uniform
- The effective length of magnet is 31.4 cm and its pole strength is 0.8Am.
- The particle executing simple harmonic motion has a kinetic energy K₀cos²ωt.
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply