| ⇦ |
| ⇨ |
If a body is rolling on the surface, its total energy will be
Options
(a)(1/2) mv² – (Gm₁m₂/R)
(b) (1/2) mv² + (1/2) Iω²
(c) (1/2) mv² – (1/2) mR²ω²
(d) None
Correct Answer:
(1/2) mv² + (1/2) Iω²
Explanation:
Total energy = P.E. + K.E. of (linear motion + Rotation)
= 0 + (1/2) mv² + (1/2) Iω²
Total energy = (1/2) mv² + (1/2) Iω².
Related Questions: - A calorimeter contains 0.2 kg of water at 30° C. 0.1kg of water at
- Angle of minimum deviation for a prism of reractive index 1.5 equal to the angle
- Two capacitors of capacitances 2 μF and 3 μF are joined in series.
- If the momentum of electron is changed by P, then the de-Broglie wavelength
- A source and an observer approach each other with same velocity 50 m/s. If the frequency
Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A calorimeter contains 0.2 kg of water at 30° C. 0.1kg of water at
- Angle of minimum deviation for a prism of reractive index 1.5 equal to the angle
- Two capacitors of capacitances 2 μF and 3 μF are joined in series.
- If the momentum of electron is changed by P, then the de-Broglie wavelength
- A source and an observer approach each other with same velocity 50 m/s. If the frequency
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply