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If a body is rolling on the surface, its total energy will be
Options
(a)(1/2) mv² – (Gm₁m₂/R)
(b) (1/2) mv² + (1/2) Iω²
(c) (1/2) mv² – (1/2) mR²ω²
(d) None
Correct Answer:
(1/2) mv² + (1/2) Iω²
Explanation:
Total energy = P.E. + K.E. of (linear motion + Rotation)
= 0 + (1/2) mv² + (1/2) Iω²
Total energy = (1/2) mv² + (1/2) Iω².
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Topics: Work Energy and Power
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A planet in a distinct solar system is 10 times more massive than the earth
- Power dissipated in an LCR series circuit connected to an a.c source of emf ? is
- A nucleus of mass number 220, initially at rest, emits an α-particle. If the Q-value
- The unit of thermal conductivity is
- A disc of radius 0.1 m is rotating with a frequency 10 rev/sec in a normal magnetic
Topics: Work Energy and Power (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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