| ⇦ | 
| ⇨ |
The escape velocity from the earth is Ve. The escape velocity from a planet whose radius is 4 times and density is 9 times that of earth is
Options
(a) 36 Ve
(b) 12 Ve
(c) 6 Ve
(d) 20 Ve
Correct Answer:
12 Ve
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - One mole of an ideal diatomic gas undergoes a transition from A to B along a path
- Complete the reaction: ₀n¹+ ₉₂U²³⁵→₅₆Ba¹⁴⁴+……..+3n
- To get three images of single object, one should have two plane mirrors at an angle of
- A piece of marble is projected from the earth’s surface with velocity of 50 m/s
- The de-Broglie wavelength of an electron moving with a velocity 1.5×10⁸ ms⁻¹ is equal
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- One mole of an ideal diatomic gas undergoes a transition from A to B along a path
- Complete the reaction: ₀n¹+ ₉₂U²³⁵→₅₆Ba¹⁴⁴+……..+3n
- To get three images of single object, one should have two plane mirrors at an angle of
- A piece of marble is projected from the earth’s surface with velocity of 50 m/s
- The de-Broglie wavelength of an electron moving with a velocity 1.5×10⁸ ms⁻¹ is equal
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply