⇦ | ![]() | ⇨ |
For a simple pendulum performing simple harmonic motion, the time period is plotted against its length. The curve will be
Options
(a) straight line
(b) circle
(c) parabola
(d) ellipse
Correct Answer:
parabola
Explanation:
Time period of a simple pendulum performing simple harmonic motion is given by
T = 2π √(l/g) where l is the length of the pendulum
or, T² = 4π²l/g or, T² ∝ l
Graph between T and l is a parabola.
Related Questions:
- A long wire carrying a steady current is bent into a circular loop of one turn.
- In gamma ray emission from a nucleus
- A sphere of 4cm radius is suspended with in a hollow sphere of 6cm radius. If the inner
- Dimensions of Torque are
- Which of the following is true for elastic potential energy density?
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply