| ⇦ |
| ⇨ |
A particle moves with constant speed v along a circular path of radius r and completes the circle in time T. The acceleration of the particle is
Options
(a) 2πv/T
(b) 2πr/T
(c) 2πr²/T
(d) 2πv²/T
Correct Answer:
2πv/T
Explanation:
Centripetal acceleration = v² / R = v × (v/R) a = v × ω (Therefore, ω = v/R) a = (v × 2π)/T.
Related Questions: - Two blocks of masses m₁=4 kg and m₂= 2kg are connected to the ends of a string
- A metal plate weighing 750g is to be electroplated with 0.05% of its weight of silver.
- Fusion reaction takes place at high temperature because
- If the r.m.s. velocity of a gas is v, then
- A beam of cathode rays is subjected to crossed Electric (E) and Magnetic fields (B)
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two blocks of masses m₁=4 kg and m₂= 2kg are connected to the ends of a string
- A metal plate weighing 750g is to be electroplated with 0.05% of its weight of silver.
- Fusion reaction takes place at high temperature because
- If the r.m.s. velocity of a gas is v, then
- A beam of cathode rays is subjected to crossed Electric (E) and Magnetic fields (B)
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply