| ⇦ | 
| ⇨ |
A particle moves with constant speed v along a circular path of radius r and completes the circle in time T. The acceleration of the particle is
Options
(a) 2πv/T
(b) 2πr/T
(c) 2πr²/T
(d) 2πv²/T
Correct Answer:
2πv/T
Explanation:
Centripetal acceleration = v² / R = v × (v/R) a = v × ω (Therefore, ω = v/R) a = (v × 2π)/T.
Related Questions: - The mean radius of the earth is R, its angular speed on its own axis is ?
- A bus is moving with a speed of 10 ms⁻¹ on a straight road
- The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV,
- Dimensions formula for surface tension is
- The decay constant of a radio isotope is λ. If A₁ and A₂ are its activities at time
Topics: Motion in Plane
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The mean radius of the earth is R, its angular speed on its own axis is ?
- A bus is moving with a speed of 10 ms⁻¹ on a straight road
- The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV,
- Dimensions formula for surface tension is
- The decay constant of a radio isotope is λ. If A₁ and A₂ are its activities at time
Topics: Motion in Plane (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply