⇦ | ⇨ |
A body of weight W newton is at the surface of the earth. Its weight at a height equal to half the radius of the earth will be
Options
(a) W/2
(b) 2W/3
(c) 4W/9
(d) 8W/27
Correct Answer:
4W/9
Explanation:
Let h=height above the earth
R=Radius of earth
Now, the acceleration due to gravity at a height ‘h’ above the earth’s surface(g) is given by
gh=g(1+h/R)⁻²
Given h=R/2
gh=g(1+R/2/R)⁻²
gh/g=1/(1+1/2)²=1/(3/2)²=(2/3)²=4/9
since g=W; gh=4/9g;4/9 W.
.
Related Questions: - Graph of force per unit length between two long parallel current carrying
- An air core coil and an electric bulb are connected in series with an AC source.
- The mean free path of molecules of a gas,(radius ‘r’) is inversely proportional to
- Current in a coil changes from 4 A to zero in 0.1 second and the emf induced is 100V
- An object is seen through a simple microscope of focal length 12 cm.
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Graph of force per unit length between two long parallel current carrying
- An air core coil and an electric bulb are connected in series with an AC source.
- The mean free path of molecules of a gas,(radius ‘r’) is inversely proportional to
- Current in a coil changes from 4 A to zero in 0.1 second and the emf induced is 100V
- An object is seen through a simple microscope of focal length 12 cm.
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply