| ⇦ | 
| ⇨ |
The half-life of radioactive element is 600 yr. The fraction of sample that would remain after 3000 yr is
Options
(a) (1/2)
(b) (1/16)
(c) (1/8)
(d) (1/32)
Correct Answer:
(1/32)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The rest mass of a body is m1. It moves with a velocity of 0.6c, then its relativistic
- The flux linked with a coil at any intant t is given by ?=10t² – 50t + 250
- A current of 5 A is passing through a metallic wire of cross-sectional area 4×10⁻⁶ m².
- Maximum velocity of the photoelectron emitted by a metal is 1.8×10⁶ ms⁻¹.
- The work function for metals A,B abd C are respectively 1.92 eV,2.0 eV and 5 eV.
Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The rest mass of a body is m1. It moves with a velocity of 0.6c, then its relativistic
- The flux linked with a coil at any intant t is given by ?=10t² – 50t + 250
- A current of 5 A is passing through a metallic wire of cross-sectional area 4×10⁻⁶ m².
- Maximum velocity of the photoelectron emitted by a metal is 1.8×10⁶ ms⁻¹.
- The work function for metals A,B abd C are respectively 1.92 eV,2.0 eV and 5 eV.
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
T(Half)=600 years
T=3000 years
n=3000/600
n=5
Now,
N=N`(1/2)powern=5
N=N'(1/32)
N/N`=1/32