⇦ | ⇨ |
An open pipe resonates with a tuning fork of frequency 500 Hz. It is observed that two successive nodes are formed at distances 16 cm and 46 cm from the open end. The speed of sound in air in the pipe is
Options
(a) 230 m/s
(b) 300 m/s
(c) 320 m/s
(d) 360 m/s
Correct Answer:
300 m/s
Explanation:
Two successive modes are separated by λ/2. λ/2 = (46-16)=30 λ=60 cm=0.6 m v=nλ=500×0.6=300 m/s.
Related Questions: - In the given figure, a diode D is connected to an external resistance R=100 Ω
- Charge density for intrinsic semiconductor will be
- Curie temperature above which
- The number of NAND gates required to form an AND gate is
- If the number of radius of ²⁷Al is 3.6 Fermi, the approximate nuclear radius
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the given figure, a diode D is connected to an external resistance R=100 Ω
- Charge density for intrinsic semiconductor will be
- Curie temperature above which
- The number of NAND gates required to form an AND gate is
- If the number of radius of ²⁷Al is 3.6 Fermi, the approximate nuclear radius
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Question explain
Two successive modes are separated by λ/2. λ/2 = (46-16)=30 λ=60 cm=0.6 m v=nλ=500×0.6=300 m/s.