| ⇦ | 
| ⇨ |
Two beams of light having intensities I and 4I interfere to produce a fringe pattern on a screen. The phase difference between the beams is π/2 at a point A and π at point B. Then the difference between the resultant intensities at A and B is
Options
(a) 2I
(b) 4I
(c) 5I
(d) 7I
Correct Answer:
4I
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - When we close one slit in the young’s double slit experiment, then
- Maximum velocity of the photoelectron emitted by a metal is 1.8×10⁶ ms⁻¹.
- The electirc field in a certain region is acting radially outward and is given by E=Ar.
- The potential energy of a system increases if work is done
- If the momentum of electron is changed by P, then the de-Broglie wavelength
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When we close one slit in the young’s double slit experiment, then
- Maximum velocity of the photoelectron emitted by a metal is 1.8×10⁶ ms⁻¹.
- The electirc field in a certain region is acting radially outward and is given by E=Ar.
- The potential energy of a system increases if work is done
- If the momentum of electron is changed by P, then the de-Broglie wavelength
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply