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An open pipe resonates with a tuning fork of frequency 500 Hz. It is observed that two successive nodes are formed at distances 16 cm and 46 cm from the open end. The speed of sound in air in the pipe is
Options
(a) 230 m/s
(b) 300 m/s
(c) 320 m/s
(d) 360 m/s
Correct Answer:
300 m/s
Explanation:
Two successive modes are separated by λ/2. λ/2 = (46-16)=30 λ=60 cm=0.6 m v=nλ=500×0.6=300 m/s.
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Topics: Waves
(80)
Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A student performs an experiment to determine the Young’s modulus of a wire
- A magnetic field of 1600 A/m produces a magnetic flux of 2.4 x 10⁻⁵ Wb
- A circular disc of radius R is removed from a bigger circular disc of radius 2R
- A uniform plank of Young’s modulus Y is moved over a smooth horizontal surface
- C and Si both have same lattice strcture, having 4 bonding electron in each
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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Question explain
Two successive modes are separated by λ/2. λ/2 = (46-16)=30 λ=60 cm=0.6 m v=nλ=500×0.6=300 m/s.