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The pair of quantities having same dimensions is
Options
(a) Young’s modulus and energy
(b) impulse and surface tension
(c) angular momentum and work
(d) work and torque
Correct Answer:
work and torque
Explanation:
Work = Force x displacement
Torque = Force x force arm
= mass x acceleration x length
= [M] x [LT⁻²] x [L] = ML²T⁻²
Related Questions: - Excitation energy of a hydrogen like ion, in its first excitation state, is 40.8 eV.
- A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field
- The radius of the first orbit of the hydrogen atom is a₀. The radius of the second orbit
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Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Physical World and Measurement
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Excitation energy of a hydrogen like ion, in its first excitation state, is 40.8 eV.
- A bar magnet is hung by a thin cotton thread in a uniform horizontal magnetic field
- The radius of the first orbit of the hydrogen atom is a₀. The radius of the second orbit
- A magnetic force acting on a charged particle of charge -2µC in a magnetic field of 2T
- A boat taken 2h to travel 8km and back in still water.If the velocity of water 4 km/h
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Physical World and Measurement (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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