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An electron of a stationary hydrogen atom passes from the fifth energy level to the ground level. The velocity that the atom acquired as a result of photon emission will be: (m is the mass of electron, R, Rydberg constant and h Planck’s constant)
Options
(a) 24hR / 25m
(b) 25hR / 24m
(c) 25m / 24hR
(d) 24m / 25hR
Correct Answer:
24hR / 25m
Explanation:
For emission, the wave no. of the radiation is given as
1/λ = Rz² (1/n₁² – 1/n₂²)
R = Rydberg constant, Z = atomic number
= R (1/1² – 1/5²) = R (1 – 1/25) ⇒ 1/λ = R 24/25
linear momentum
P = h/λ = h x R x 24/25 (de-Broglie hypothesis)
⇒ mv = 24hR / 25 ⇒ V = 24hR / 25m
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- To convert a 800 mV range millivoltmeter of resistance 40Ω into an ammeter of 100 mA
- An atom bomb weighing 1 kg explodes releasing 9×10¹³ J of energy.
- The de-Broglie wavelength of an electron is the same as that of a 50 KeV X-ray photon.
- Work done by an external agent in separating the parallel plate capacitor is
- Two racing cars of masses m₁ and m₂ are moving in circles of radii
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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