| ⇦ | 
| ⇨ |
The threshold frequency for a photosensitive metal is 3.3 x 10¹⁴ Hz. If light of frequency 8.2 x 10¹⁴ Hz incident on this metal, the cut-off voltage for the photoelectric emission is nearly
Options
(a) 2 V
(b) 3 V
(c) 5 V
(d) 1 V
Correct Answer:
2 V
Explanation:
K.E = hv – hvₜₕ = eV₀ ( V₀ = cut off voltage)
V₀ = h/e (8.2 x 10¹⁴ – 3.3 x 10¹⁴)
= 6.6 x 10⁻³⁴ x 4.9 x 10¹⁴ / 1.6 x 10⁻¹⁹ = 2 V
Related Questions: - The acceleration due to gravity near the surface of a planet of radius R and density d
- A carnot engine working between 300 K and 600 K has a work output of 800J per cycle.
- A 100Ω resistance and a capacitor of 100Ω reactance are connected in series
- A particle of mass m moves with constant speed along a circular path of radius r under
- The unit of surface tension is
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The acceleration due to gravity near the surface of a planet of radius R and density d
- A carnot engine working between 300 K and 600 K has a work output of 800J per cycle.
- A 100Ω resistance and a capacitor of 100Ω reactance are connected in series
- A particle of mass m moves with constant speed along a circular path of radius r under
- The unit of surface tension is
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply