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An electron in the hydrogen atom jumps from excited state n to the ground state. The wavelength so emitted illuminates a photosensitive material having work function 2.75 eV. If the stopping potential of the photoelectron is 10 V, the value of n is
Options
(a) 3
(b) 4
(c) 5
(d) 2
Correct Answer:
4
Explanation:
KEₘₐₓ = 10 eV ? = 2.75 eV
Total incident energy
E = ? + KEₘₐₓ = 12.75 eV
Energy is released when electron jumps from the excited state n to the ground state.
E₄ – E₁ = {-0.85 – (-13.6) eV}
= 12.75 eV value of n = 4.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂,
- A battery of e.m.f. E and internal resistance r is connected to an external resistance
- A uniform rope of length 12 m and mass 6 kg hangs vertically from a rigid support.
- If a solid ball of metal has a concentric spherical cavity with in it if the ball
- Copper and carbon wires are connected in series and the combined resistor is kept
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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