| ⇦ |
| ⇨ |
In a parallel plate capacitor with plate area A and charge Q, the force on one plate because of the charge on the other is equal to
Options
(a) Q²/ε₀A²
(b) Q²/2ε₀A²
(c) Q²/ε₀A
(d) Q²/2ε₀A
Correct Answer:
Q²/2ε₀A
Explanation:
Force between the plates of a parallel plate capacitor |F| = V²A / 2ε₀ = Q² / 2ε₀A
Related Questions: - Which of the following combinations should be selected for better tuning of an L-C-R
- A hollow sphere of radius 0.1m has a charge of 5×10⁻⁸C. The potential
- What is the value of Ā+A in the Boolean algebra?
- A particle moves along with x-axis.The position x of particle with respect to time
- If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following combinations should be selected for better tuning of an L-C-R
- A hollow sphere of radius 0.1m has a charge of 5×10⁻⁸C. The potential
- What is the value of Ā+A in the Boolean algebra?
- A particle moves along with x-axis.The position x of particle with respect to time
- If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply