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In a parallel plate capacitor with plate area A and charge Q, the force on one plate because of the charge on the other is equal to
Options
(a) Q²/ε₀A²
(b) Q²/2ε₀A²
(c) Q²/ε₀A
(d) Q²/2ε₀A
Correct Answer:
Q²/2ε₀A
Explanation:
Force between the plates of a parallel plate capacitor |F| = V²A / 2ε₀ = Q² / 2ε₀A
Related Questions: - To demonstrate the phenomenon of interference, we require two sources which emit
- Two bulbs 40 watt and 60 watt and rated voltage 240 V are connected in series
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- To demonstrate the phenomenon of interference, we require two sources which emit
- Two bulbs 40 watt and 60 watt and rated voltage 240 V are connected in series
- Three capacitors each of capacity 4 μF are to be connected in such a way that the effective
- Which of the following quantities has units but not dimensions
- A wire of length L metre carrying a current I ampere is bent in the form
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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