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In a parallel plate capacitor with plate area A and charge Q, the force on one plate because of the charge on the other is equal to
Options
(a) Q²/ε₀A²
(b) Q²/2ε₀A²
(c) Q²/ε₀A
(d) Q²/2ε₀A
Correct Answer:
Q²/2ε₀A
Explanation:
Force between the plates of a parallel plate capacitor |F| = V²A / 2ε₀ = Q² / 2ε₀A
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Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- To convert a 800 mV range millivoltmeter of resistance 40Ω into an ammeter of 100 mA
- Light of wavelength 500 nm is incident on a metal with work function 2.28 eV.
- The Kα X-ray of molybdenum has a wavelength of 71×10⁻¹² m. If the energy of a molybdenum
- Charge passing through a conductor of cross-section area A=0.3 m² is given
- As a result of interference of two coherent sources of light, energy is
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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