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An electron in hydrogen atom makes a transition n₁ → n₂ where n₁ and n₂ are principal quantum number of the two states. Assuming Bohr’s model to be valid the time period of the electron in the initial state is eight times that in the final state. The possible values of n₁ and n₂ are
Options
(a) n₁ = 4 and n₂ = 2
(b) n₁ = 6 and n₂ = 2
(c) n₁ = 8 and n₂ = 1
(d) n₁ = 8 and n₂ = 2
Correct Answer:
n₁ = 4 and n₂ = 2
Explanation:
T ∞ n³
Tn₁ = 8 Tn₂ (given)
Hence, n₁ = 2n₂
Related Questions: - The wavelength of Kα line in copper is 1.5Å. The ionisation energy of K electron in copper is
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The wavelength of Kα line in copper is 1.5Å. The ionisation energy of K electron in copper is
- We get Balmer series when electron comes from
- Complete the reaction: ₀n¹+ ₉₂U²³⁵→₅₆Ba¹⁴⁴+……..+3n
- A particle starts its motion from rest under the action of a constant force
- Bragg’s law for X-rays is
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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