⇦ | ⇨ |
An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into a dielectric medium with relative permittivity ε = 4.0. Then
Options
(a) wavelength is doubled and frequency is unchanged
(b) wavelength is doubled and frequency becomes half
(c) wavelength is halved and frequency remains unchanged
(d) wavelength and frequency both remain unchanged
Correct Answer:
wavelength is halved and frequency remains unchanged
Explanation:
Given : frequency f = 2 MHz, relative permitivity εᵣ = 4
For formula,
velocity v = c / √εᵣ = c / 2
λ’ = λ / 2
[since frequency remains unchanged ]
Related Questions: - 1 a.m.u. is equivalent to
- Order of e/m ratio of proton, α-particle and electron is
- The de-Broglie wavelength of an electron having 80 eV of energy is nearly
- A long solenoid has 500 turns. When a current of 2 ampere is passed through it
- If the half-life of a material is 10 yr, then in what time, it becomes 1/4th part
Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 1 a.m.u. is equivalent to
- Order of e/m ratio of proton, α-particle and electron is
- The de-Broglie wavelength of an electron having 80 eV of energy is nearly
- A long solenoid has 500 turns. When a current of 2 ampere is passed through it
- If the half-life of a material is 10 yr, then in what time, it becomes 1/4th part
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply