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An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into a dielectric medium with relative permittivity ε = 4.0. Then
Options
(a) wavelength is doubled and frequency is unchanged
(b) wavelength is doubled and frequency becomes half
(c) wavelength is halved and frequency remains unchanged
(d) wavelength and frequency both remain unchanged
Correct Answer:
wavelength is halved and frequency remains unchanged
Explanation:
Given : frequency f = 2 MHz, relative permitivity εᵣ = 4
For formula,
velocity v = c / √εᵣ = c / 2
λ’ = λ / 2
[since frequency remains unchanged ]
Related Questions: - If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum
- A and B are two metals with threshold frequencies 1.8 x 10¹⁴ Hz and 2.2 x 10¹⁴ Hz.
- If R is the radius of earth, the height at which the weight of a body 1/4 of its weight
- what is the electric potential at a distance of 9cm from 3nC?
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Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum
- A and B are two metals with threshold frequencies 1.8 x 10¹⁴ Hz and 2.2 x 10¹⁴ Hz.
- If R is the radius of earth, the height at which the weight of a body 1/4 of its weight
- what is the electric potential at a distance of 9cm from 3nC?
- The Bohr model of atoms
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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