⇦ | ⇨ |
what is the electric potential at a distance of 9cm from 3nC?
Options
(a) 270V
(b) 3V
(c) 300V
(d) 30V
Correct Answer:
300V
Explanation:
Given, q = 3 nC = 3 × 10⁻⁹ C and r = 9 cm = 9 × 10⁻² m
We know that, potential due to point charge is given by V = (1 / 4πε₀) (q / r)
= (9 × 10⁹ × 3 × 10⁻⁹) / 9 × 10⁻² = 3 × 10²
⇒ Electric potential, V = 300 V
Related Questions: - An object is projected with a velocity of 20 m/s making an angle of 45⁰ with horizontal.
- The ratio of volumes of nuclei (assumed to be in spherical shape) with respective
- Two bodies of masses m₁ and m₂ and having velocities v₁ and v₂ respectively
- If h is planck’s constant and λ is wavelength, h/λ has dimensions of
- A photon of energy 10.2 eV collide inelastically with hydrogen atom in ground state
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An object is projected with a velocity of 20 m/s making an angle of 45⁰ with horizontal.
- The ratio of volumes of nuclei (assumed to be in spherical shape) with respective
- Two bodies of masses m₁ and m₂ and having velocities v₁ and v₂ respectively
- If h is planck’s constant and λ is wavelength, h/λ has dimensions of
- A photon of energy 10.2 eV collide inelastically with hydrogen atom in ground state
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply