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A tuning fork vibrates with 2 beats in 0.04 second. The frequency of the fork is
Options
(a) 50 Hz
(b) 100 Hz
(c) 80 Hz
(d) None of these
Correct Answer:
50 Hz
Explanation:
Beats / sec = difference of frequencies
2 / 0.04 = frequency difference
Frequency difference = 2 × 100 / 4 = 50 Hz
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If a magnetic substance is brought near the north or the south pole of a bar magnet
- In a vessel, the gas is at a pressure P. If the mass of all the molecules
- Electric potential at any point is V= -5x +3y + √(15) z. Then the magnitude of electric
- Three cells, each of e.m.f 1.5 V and internal resistance 1 ohm are connected in parallel
- Volume of gas becomes four times if temperature becomes
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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