| ⇦ | 
| ⇨ |
A tuning fork vibrates with 2 beats in 0.04 second. The frequency of the fork is
Options
(a) 50 Hz
(b) 100 Hz
(c) 80 Hz
(d) None of these
Correct Answer:
50 Hz
Explanation:
Beats / sec = difference of frequencies
2 / 0.04 = frequency difference
Frequency difference = 2 × 100 / 4 = 50 Hz
Related Questions: - The electromagnetic waves detected using a thermopile and used in physical therapy
- The magnetic field at a point on the axis of a long solenoid having 5 turns per cm
- For a cubic crystal structure which one of the following relations
- The velocity of molecules of a gas at temperature 120 K is v. At what temperature
- An alternating emf given by equation
e=300 sin[(100 π)t] V
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The electromagnetic waves detected using a thermopile and used in physical therapy
- The magnetic field at a point on the axis of a long solenoid having 5 turns per cm
- For a cubic crystal structure which one of the following relations
- The velocity of molecules of a gas at temperature 120 K is v. At what temperature
- An alternating emf given by equation e=300 sin[(100 π)t] V
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply