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A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string of a piano. The beat frequency decreases to 2 beats per sec when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was
Options
(a) 510 Hz
(b) 514 Hz
(c) 516 Hz
(d) 508 Hz
Correct Answer:
508 Hz
Explanation:
The frequency of the piano string = 512+-4 = 516 or 508. When the tension is increased, beat frequency decreases to 2, it means that frequency of othe string is 508 as frequency of string increases with tension.
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- One-fourth length of a spring of force constant K is cut away. The force constant
- Water rises in a vertical capillary tube up to a height of 2.0 cm.
- The molar specific heat at constant pressure of an ideal gas is (7/2)R. The ratio
- λ₁ and λ₂ are used to illuminate the slits. β₁ and β₂ are the corresponding fringe
- A block of mass 0.50 kg is moving with a speed of 2.00 ms⁻¹ on a smooth surface.
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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