| ⇦ | 
| ⇨ |
The speed of an electron having a wavelength of 10⁻¹⁰ m is
Options
(a) 6.26×10⁶ m/s
(b) 5.25 x10⁶ m/s
(c) 7.25×10⁶ m/s
(d) 4.24×10⁶ m/s
Correct Answer:
7.25×10⁶ m/s
Explanation:
λ = h / momentum = h / mv
v = h / mλ = 6.6 × 10⁻³⁴ / (9 × 10⁻³¹) × 10⁻¹°
v = 7.25 × 10⁶ ms⁻¹
Related Questions: - The horizontal range and maximum height of a projectile are equal.The angle of projection
- Spectrum of X-rays is
- The self-inductance of a choke coil is 10 mH. When it is connected with a 10 V DC source,
- A 50 ohm galvanometer gets full scale deflection when a current of 0.01 A passes
- The input characteristics of a transistor in CE mode is the graph obtained by plotting
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The horizontal range and maximum height of a projectile are equal.The angle of projection
- Spectrum of X-rays is
- The self-inductance of a choke coil is 10 mH. When it is connected with a 10 V DC source,
- A 50 ohm galvanometer gets full scale deflection when a current of 0.01 A passes
- The input characteristics of a transistor in CE mode is the graph obtained by plotting
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
P=h/lamba…..1equ
P= momentum
H=Planck’s constant
Lamba= wavelength
And
P=MV…..2 equ
M= mass
V= speed
Put 2 in 1
MV=h/lamba
9.1×10^-31*v=6.6×10^-34/10^-10
By solving u get the value of v
V=0.725*10^7=7.25*10^6