| ⇦ |
| ⇨ |
The speed of an electron having a wavelength of 10⁻¹⁰ m is
Options
(a) 6.26×10⁶ m/s
(b) 5.25 x10⁶ m/s
(c) 7.25×10⁶ m/s
(d) 4.24×10⁶ m/s
Correct Answer:
7.25×10⁶ m/s
Explanation:
λ = h / momentum = h / mv
v = h / mλ = 6.6 × 10⁻³⁴ / (9 × 10⁻³¹) × 10⁻¹°
v = 7.25 × 10⁶ ms⁻¹
Related Questions: - An object is attached to the bottom of a light vertical spring and set vibrating.
- Steam at 100⁰C is passed into 20 g of water at 10°C. When water acquires a temperature
- If n₁, n₂ and n₃ are the fundamental frequencies of three segments into which a string
- A coil of resistance and 1.0 H inductance is connected to an a.c. source of frequency
- The cadmium rods are used in nuclear reactor to
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An object is attached to the bottom of a light vertical spring and set vibrating.
- Steam at 100⁰C is passed into 20 g of water at 10°C. When water acquires a temperature
- If n₁, n₂ and n₃ are the fundamental frequencies of three segments into which a string
- A coil of resistance and 1.0 H inductance is connected to an a.c. source of frequency
- The cadmium rods are used in nuclear reactor to
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

P=h/lamba…..1equ
P= momentum
H=Planck’s constant
Lamba= wavelength
And
P=MV…..2 equ
M= mass
V= speed
Put 2 in 1
MV=h/lamba
9.1×10^-31*v=6.6×10^-34/10^-10
By solving u get the value of v
V=0.725*10^7=7.25*10^6