| ⇦ | 
| ⇨ |
A transverse wave is represented by y = a sin (?t – kx). For what value of the wavelength is the wave velocity equal to the maximum particle velocity?
Options
(a) πA / 2
(b) π A
(c) 2π A
(d) A
Correct Answer:
2π A
Explanation:
y = A sin ( ?t – kx ) particle velocity,
vₚ = dy/ dt = A ? cos ( ?t – kx )
vₚ ₘₐₓ = A ? wave velocity = ? / k
A ? = ? / k i.e., A = 1/k But k = 2π / λ
λ = 2π A
Related Questions: - The ratio of radii of planets A and B is K₁ and ratio of accelerations
- In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency
- A block of mass m1 rests on a horizontal table. A light string connected
- A small rod of bismuth is suspended freely between the poles of a strong electromagnet.
- To get three images of single object, one should have two plane mirrors at an angle of
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of radii of planets A and B is K₁ and ratio of accelerations
- In an LCR circuit, capacitance is changed from C to 2C. For the resonant frequency
- A block of mass m1 rests on a horizontal table. A light string connected
- A small rod of bismuth is suspended freely between the poles of a strong electromagnet.
- To get three images of single object, one should have two plane mirrors at an angle of
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply