| ⇦ | 
| ⇨ |
A thin ring of radius R meter has charge q coulomb uniformly spread on it. The ring rotates about its axis with a constant frequency of f revolutions/s. The value of magnetic induction in Wb/m² at the centre of the ring is
Options
(a) µ₀q f / 2π R
(b) µ₀q / 2π f R
(c) µ₀q / 2 f R
(d) µ₀q f / 2 R
Correct Answer:
µ₀q f / 2 R
Explanation:
Current in the ring due to the rotation,
I = q/T = q? / 2π = q.2π f / 2π
Therefore, magnetic field at the centre of the ring is
B = µ₀I / 2R = µ₀/2R . q2π f / 2π
= µ₀q f / 2 R
Related Questions: - Weber/m² is equal to
- The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV,
- If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits
- If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV
- The power factor of an AC circuit having resistance R and inductance L connected
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Weber/m² is equal to
- The threshold frequency for a metallic surface corresponds to an energy of 6.2 eV,
- If an electron in a hydrogen atom jumps from the 3rd orbit to the 2nd orbit, it emits
- If the binding energy of the nucleon in ₃⁷Li and ₂⁴He nuclei are 5.60 MeV and 7.06 MeV
- The power factor of an AC circuit having resistance R and inductance L connected
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply