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A thin ring of radius R meter has charge q coulomb uniformly spread on it. The ring rotates about its axis with a constant frequency of f revolutions/s. The value of magnetic induction in Wb/m² at the centre of the ring is
Options
(a) µ₀q f / 2π R
(b) µ₀q / 2π f R
(c) µ₀q / 2 f R
(d) µ₀q f / 2 R
Correct Answer:
µ₀q f / 2 R
Explanation:
Current in the ring due to the rotation,
I = q/T = q? / 2π = q.2π f / 2π
Therefore, magnetic field at the centre of the ring is
B = µ₀I / 2R = µ₀/2R . q2π f / 2π
= µ₀q f / 2 R
Related Questions: - When two displacements represented by y₁=a sin(?t) are superimposed the motion is
- A galvanometer has a coil of resistance 100 ohm and gives a full-scale deflection
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Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When two displacements represented by y₁=a sin(?t) are superimposed the motion is
- A galvanometer has a coil of resistance 100 ohm and gives a full-scale deflection
- If two vectors are equal in magnitude and their resultant is also equal in magnitude
- If energy(E), velocity(V) and time(T) are chosen as fundamental quantities,
- The dimensions of latent heat are
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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