⇦ | ⇨ |
A thin ring of radius R meter has charge q coulomb uniformly spread on it. The ring rotates about its axis with a constant frequency of f revolutions/s. The value of magnetic induction in Wb/m² at the centre of the ring is
Options
(a) µ₀q f / 2π R
(b) µ₀q / 2π f R
(c) µ₀q / 2 f R
(d) µ₀q f / 2 R
Correct Answer:
µ₀q f / 2 R
Explanation:
Current in the ring due to the rotation,
I = q/T = q? / 2π = q.2π f / 2π
Therefore, magnetic field at the centre of the ring is
B = µ₀I / 2R = µ₀/2R . q2π f / 2π
= µ₀q f / 2 R
Related Questions: - A magnifying glass of focal length 5 cm is used to view an object by a person
- Newton postulated his corpuscular theory on the basis of
- If a small amount of antimony is added to germanium crystal
- Which one of the following statements is true, if half-life of a radioactive substance
- In a LCR series circuit, the potential difference between the terminals of the inductor
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A magnifying glass of focal length 5 cm is used to view an object by a person
- Newton postulated his corpuscular theory on the basis of
- If a small amount of antimony is added to germanium crystal
- Which one of the following statements is true, if half-life of a radioactive substance
- In a LCR series circuit, the potential difference between the terminals of the inductor
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply