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A beam of cathode rays is subjected to crossed Electric(E) and Magnetic fields(B). The fields are adjusted such that the beam is not deflected. The specific charge of the cathode rays is given by: (Where V is the potential difference between cathode and anode).
Options
(a) B² / 2VE²
(b) 2VB² / E²
(c) 2VE² / B²
(d) E² / 2VB²
Correct Answer:
E² / 2VB²
Explanation:
For no deflection of beam, eE = evB ⇒ v = E/B
Also, 1/2 mv² = eV ⇒ v = E/B
e/m = v² / 2V = E² / 2VB²
Related Questions: - Photons of 5.5 eV energy fall on the surface of the metal emitting photoelectrons
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Photons of 5.5 eV energy fall on the surface of the metal emitting photoelectrons
- Match the following columns about collision
- A beaker of radius 1.5 cm is filled with a liquid of surface tension 0.075 N/m
- The turn ratio of a transformer is 1:2. An electrolytic dc cell of emf 2 volt is connected
- A particle of masses m is thrown upwards from the surface of the earth, with a velocity u
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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