| ⇦ | 
| ⇨ |
A straight conductor 0.1 m long moves in a uniform magnetic field 0.1 T. The velocity of the conductor is 15 ms⁻¹ and is directed perpendicular to the field. The emf indued between the two ends of the conductor is
Options
(a) 0.10 V
(b) 0.15 V
(c) 1.50 V
(d) 15 V
Correct Answer:
0.15 V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Three capacitors each of capacitance C and of breakdown voltage V are joined in series
- Photocells convert
- The work function of a substance is 4.0 eV. The longest wavelength of light
- A person holding a rifle (mass of person and rifle together is 100 kg) stands on a smooth
- A man measures time period of a pendulum(T) in stationary lift. If the lift moves upwards
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three capacitors each of capacitance C and of breakdown voltage V are joined in series
- Photocells convert
- The work function of a substance is 4.0 eV. The longest wavelength of light
- A person holding a rifle (mass of person and rifle together is 100 kg) stands on a smooth
- A man measures time period of a pendulum(T) in stationary lift. If the lift moves upwards
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply