| ⇦ | 
| ⇨ |
A straight conductor 0.1 m long moves in a uniform magnetic field 0.1 T. The velocity of the conductor is 15 ms⁻¹ and is directed perpendicular to the field. The emf indued between the two ends of the conductor is
Options
(a) 0.10 V
(b) 0.15 V
(c) 1.50 V
(d) 15 V
Correct Answer:
0.15 V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Curie temperature above which
- A particle moves a distance x in time t according to equation x = (t + 5)⁻¹
- If the number of radius of ²⁷Al is 3.6 Fermi, the approximate nuclear radius
- Four indentical thin rods each of mass M and length l, form a square frame
- Given a sample of radium-226 having half-life of 4 days. Find the probability,
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Curie temperature above which
- A particle moves a distance x in time t according to equation x = (t + 5)⁻¹
- If the number of radius of ²⁷Al is 3.6 Fermi, the approximate nuclear radius
- Four indentical thin rods each of mass M and length l, form a square frame
- Given a sample of radium-226 having half-life of 4 days. Find the probability,
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply