| ⇦ |
| ⇨ |
A straight conductor 0.1 m long moves in a uniform magnetic field 0.1 T. The velocity of the conductor is 15 ms⁻¹ and is directed perpendicular to the field. The emf indued between the two ends of the conductor is
Options
(a) 0.10 V
(b) 0.15 V
(c) 1.50 V
(d) 15 V
Correct Answer:
0.15 V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The physical quantity which does not have the same dimensions as the other three is
- If, an electron in hydrogen atom jumps from an orbit of level n=3 to an orbit
- Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂,
- An electric dipole of dipole moment p is aligned parallel to a uniform electric field E
- The order of the electric field near the earth’s surface is
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The physical quantity which does not have the same dimensions as the other three is
- If, an electron in hydrogen atom jumps from an orbit of level n=3 to an orbit
- Two spherical nuclei have mass numbers 216 and 64 with their radii R₁ and R₂,
- An electric dipole of dipole moment p is aligned parallel to a uniform electric field E
- The order of the electric field near the earth’s surface is
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply