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The phase difference between two points seperated by 0.8 m in a wave of frequency 120 Hz is 0.5 π. The wave velocity is
Options
(a) 144 m/s
(b) 256 m/s
(c) 384 m/s
(d) 720 m/s
Correct Answer:
384 m/s
Explanation:
Phase difference = 2π/λ × Path difference
0.5π = 2π/λ × 0.8 m or λ = (2π × 0.8 m) / 0.5π = 3.2 m
Velocity v = frequency (ʋ) × Wavelength (λ)
= 120 Hz × 3.2 m = 384 m/s.
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A coil of inductive reactance 31 Ω has a resistance of 8 Ω. It is placed in series
- Light of wavelength λᴀ and λᴃ falls on two identical metal plates A and B respectively.
- Calculate power output of ₉₂²³⁵U reactor, if it takes 30 days to use up 2 kg of fuel,
- The horizontal and vertical components of earth’s magnetic field at a place
- A car is moving in a circular horizontal track of radius 10.0 m with a constant speed
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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