| ⇦ | 
| ⇨ |
The phase difference between two points seperated by 0.8 m in a wave of frequency 120 Hz is 0.5 π. The wave velocity is
Options
(a) 144 m/s
(b) 256 m/s
(c) 384 m/s
(d) 720 m/s
Correct Answer:
384 m/s
Explanation:
Phase difference = 2π/λ × Path difference
0.5π = 2π/λ × 0.8 m or λ = (2π × 0.8 m) / 0.5π = 3.2 m
Velocity v = frequency (ʋ) × Wavelength (λ)
= 120 Hz × 3.2 m = 384 m/s.
Related Questions: - An explosion breaks a rock into three parts in a horizontal plane
- Huygen’s wave theory could not explain
- The wavelength λₑ of an electron and λₚ of a photon are of same energy E are related by
- A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
- Three particles A,B and C are thrown from the top of a tower with the same speed.
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An explosion breaks a rock into three parts in a horizontal plane
- Huygen’s wave theory could not explain
- The wavelength λₑ of an electron and λₚ of a photon are of same energy E are related by
- A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
- Three particles A,B and C are thrown from the top of a tower with the same speed.
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply