| ⇦ | 
| ⇨ |
The phase difference between two points seperated by 0.8 m in a wave of frequency 120 Hz is 0.5 π. The wave velocity is
Options
(a) 144 m/s
(b) 256 m/s
(c) 384 m/s
(d) 720 m/s
Correct Answer:
384 m/s
Explanation:
Phase difference = 2π/λ × Path difference
0.5π = 2π/λ × 0.8 m or λ = (2π × 0.8 m) / 0.5π = 3.2 m
Velocity v = frequency (ʋ) × Wavelength (λ)
= 120 Hz × 3.2 m = 384 m/s.
Related Questions: - A circular disc of radius R is removed from a bigger circular disc of radius 2R
- A projectile is fired from the surface of the earth with a velocity of 5 m s⁻¹ and angle
- The amplitude of S.H.M. y=2 (sin 5πt+√2 cos 5πt) is
- The electric and magnetic field assiciated with an E.M. wave
- A particle has initial velocity(3i⃗ +4j⃗)and has acceleration (0.4i⃗ +0.3j⃗)
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A circular disc of radius R is removed from a bigger circular disc of radius 2R
- A projectile is fired from the surface of the earth with a velocity of 5 m s⁻¹ and angle
- The amplitude of S.H.M. y=2 (sin 5πt+√2 cos 5πt) is
- The electric and magnetic field assiciated with an E.M. wave
- A particle has initial velocity(3i⃗ +4j⃗)and has acceleration (0.4i⃗ +0.3j⃗)
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply