| ⇦ | 
| ⇨ |
A long solenoid has 500 turns. When a current of 2 ampere is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4×10⁻³ Wb. The self-inductance of the solenoid is
Options
(a) 1.0 henry
(b) 4.0 henry
(c) 2.5 henry
(d) 2.0 henry
Correct Answer:
1.0 henry
Explanation:
Total no. of turns in the solenoid,
N = 500 Currrent, I = 2A.
magnetic flux linked with each turn = 4 x 10⁻³ Wb
As, ? = LI or N ? = LI ⇒ L = N? / I
= 500 x 4 x 10⁻³ / 2 henry = 1 H
Related Questions: - Current in a coil changes from 4 A to zero in 0.1 second and the emf induced is 100V
- A sample of HCl gas is placed in an electric field of 5 x 10⁴ N/C
- When a ceiling fan is switched off its angular velocity reduces to 50% while
- A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length
- The 6563 Å line emitted by hydrogen atom in a star is found to be red shifted by 5Å
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Current in a coil changes from 4 A to zero in 0.1 second and the emf induced is 100V
- A sample of HCl gas is placed in an electric field of 5 x 10⁴ N/C
- When a ceiling fan is switched off its angular velocity reduces to 50% while
- A solenoid 1.5 m long and 0.4 cm in diameter possesses 10 turns per cm length
- The 6563 Å line emitted by hydrogen atom in a star is found to be red shifted by 5Å
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply