| ⇦ | 
| ⇨ |
A long solenoid has 500 turns. When a current of 2 ampere is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4×10⁻³ Wb. The self-inductance of the solenoid is
Options
(a) 1.0 henry
(b) 4.0 henry
(c) 2.5 henry
(d) 2.0 henry
Correct Answer:
1.0 henry
Explanation:
Total no. of turns in the solenoid,
N = 500 Currrent, I = 2A.
magnetic flux linked with each turn = 4 x 10⁻³ Wb
As, ? = LI or N ? = LI ⇒ L = N? / I
= 500 x 4 x 10⁻³ / 2 henry = 1 H
Related Questions: - A uniform wire of resistance 9Ω is joined end-to-end to form a circle. Then
- When two small bubbles join to form a bigger one, energy is
- Radius of first orbit of the electron in a hydrogen atom is 0.53 Å. So the radius
- In a circuit, 5% of total current passes through a galvanometer. If resistance
- The ratio of the numerical value of the average velocity and average speed
Topics: Electromagnetic Induction
(76)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A uniform wire of resistance 9Ω is joined end-to-end to form a circle. Then
- When two small bubbles join to form a bigger one, energy is
- Radius of first orbit of the electron in a hydrogen atom is 0.53 Å. So the radius
- In a circuit, 5% of total current passes through a galvanometer. If resistance
- The ratio of the numerical value of the average velocity and average speed
Topics: Electromagnetic Induction (76)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply