| ⇦ | 
| ⇨ |
A sound absorber attenuates the sound level by 20 dB. The intensity decreases by a factor of
Options
(a) 100
(b) 1000
(c) 10000
(d) 10
Correct Answer:
100
Explanation:
L₁ = 10 log (I₁ / I₀) ; L₂ = 10 log (I₂ / I₀)
L₁ – L₂ = 10 log (I₁ / I₀) – 10 log (I₂ / I₀)
Δ L = 10 log (I₁ / I₂)
20 dB = 10 log (I₁ / I₂)
10 ² = (I₁ / I₂)
I₂ = I₁ / 100.
Related Questions: - Two particles A and B having equal charges +6C, after being accelerated
- The masses of three wires of copper are in the ratio 1:3:5 and lengths
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two particles A and B having equal charges +6C, after being accelerated
- The masses of three wires of copper are in the ratio 1:3:5 and lengths
- The periodic waves of intensities I₁ and I₂ pass through a region at the same time
- Which of the following is suitable for the fusion process?
- A layer of glycerine of thickness 1 mm present between a large surface area of 0.1 m².
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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