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A simple pendulum performs simple harmonic motion about x = 0 with an amplitude a and time period T. The speed of the pendulum at x = a/2 will be:
Options
(a) πa / T
(b) 3π²a / T
(c) πa√3 / T
(d) πa√3 / 2T
Correct Answer:
πa√3 / T
Explanation:
Speed v = ? √(a² – x²) , x = a / 2
v = ? √(a² – a² / 4) = ? √(3a² / 4) = 2π / T . a√3 / 2
πa√3 / T
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A p-n photodiode is fabricated from a semiconductor with a band gap of 2.5 eV.
- The time period of a simple pendulum in a lift descending with constant acceleration g is
- An electric motor operating on a 60 volt D.C supply draws a current of 10 amp.
- A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same
- An object is placed at a distance of 10 cm from a co-axial combination of two lenses
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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