| ⇦ |
| ⇨ |
The position x of a particle with respect to time t along x-axis is given by x = 9t² – t³ where x is in metres and t in second. What will be the position of this particle when it achieves maximum speed along the +ve x direction?
Options
(a) 54 m
(b) 81 m
(c) 24 m
(d) 32 m
Correct Answer:
54 m
Explanation:
Speed v = dx/ dt = d/ dt (9t² – t³) = 18t – 3t² For maximum speed
dv/ dt = 0 ⇒ 18 – 6t = 0 ⇒ t= 3
⇒Xmax = 81 – 27 = 54
Related Questions: - A particle moves in a circle of radius 5 cm with constant speed and time period
- The rate of increase of thermo-e.m.f. with temperature at the neutral temperature
- The potential energy of particle in a force field is U = A/r² – b/r, where A and B
- Two radiations of photons energies 1 eV and 2.5 eV, successively
- Three objects A,B and C are kept in a straight line on a frictionless horizontal surface
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moves in a circle of radius 5 cm with constant speed and time period
- The rate of increase of thermo-e.m.f. with temperature at the neutral temperature
- The potential energy of particle in a force field is U = A/r² – b/r, where A and B
- Two radiations of photons energies 1 eV and 2.5 eV, successively
- Three objects A,B and C are kept in a straight line on a frictionless horizontal surface
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply