| ⇦ | 
| ⇨ |
A particle executing simple harmonic motion of amplitude 5 cm has maximum speed of 31.4 cm/s. The frequency of its oscillation is
Options
(a) 4 Hz
(b) 3 Hz
(c) 2 Hz
(d) 1 Hz
Correct Answer:
1 Hz
Explanation:
a = 5 cm, vₘₐₓ = 31.4 cm/s
vₘₐₓ = ωa ⇒ 31.4 = 2πʋ × 5
⇒ 31.4 = 10 × 31.4 × ʋ
⇒ ʋ = 1 Hz
Related Questions: - An electron having charge e and mass m is moving in a uniform electric field E.
- The radius of gyration of a solid sphere of radius r about a certain axis is r
- The magnetic flux linked with a circuit of resistance 100Ω increases from 10 to 60 Wb.
- The voltage of clouds is 4×10⁶ volt with respect to ground. In a lightening
- Two bodies of mass 10 kg and 5 kg moving in concentric orbits of radius
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electron having charge e and mass m is moving in a uniform electric field E.
- The radius of gyration of a solid sphere of radius r about a certain axis is r
- The magnetic flux linked with a circuit of resistance 100Ω increases from 10 to 60 Wb.
- The voltage of clouds is 4×10⁶ volt with respect to ground. In a lightening
- Two bodies of mass 10 kg and 5 kg moving in concentric orbits of radius
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply