| ⇦ | 
| ⇨ |
In L-C-R series circuit, an alternating emf e and current i are given by the equations e=100 sin (100t) V.
i=100 sin(100t+π/3)mA .
The average power dissipated in the circuit will be
Options
(a) 100 W
(b) 10 W
(c) 5 W
(d) 2.5 W
Correct Answer:
2.5 W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle moves in a straight line with a constant acceleration
- The horizontal and vertical components of earth’s magnetic field at a place
- The conducting loop in the form of a circle is placed in a uniform magneitc field
- A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same
- The total kinetic energy of a body of mass 10 kg and radius 0.5 m moving with a velocity
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moves in a straight line with a constant acceleration
- The horizontal and vertical components of earth’s magnetic field at a place
- The conducting loop in the form of a circle is placed in a uniform magneitc field
- A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same
- The total kinetic energy of a body of mass 10 kg and radius 0.5 m moving with a velocity
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply