| ⇦ | 
| ⇨ |
In L-C-R series circuit, an alternating emf e and current i are given by the equations e=100 sin (100t) V.
i=100 sin(100t+π/3)mA .
The average power dissipated in the circuit will be
Options
(a) 100 W
(b) 10 W
(c) 5 W
(d) 2.5 W
Correct Answer:
2.5 W
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In Young’s double slit experiment the distance between the slits and the screen
- A projectile is thrown in the upward direction making an angle of 60°with the horizontal
- A bar magnet of pole strength 10 A-m is cut into two equal parts breadthwise.
- In a Rutherford scattering experiment when a projectile of charge Z₁ and mass M₁
- A black body at a temperature of 227⁰C radiates heat at a rate of 20 cal m⁻²s⁻¹.
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In Young’s double slit experiment the distance between the slits and the screen
- A projectile is thrown in the upward direction making an angle of 60°with the horizontal
- A bar magnet of pole strength 10 A-m is cut into two equal parts breadthwise.
- In a Rutherford scattering experiment when a projectile of charge Z₁ and mass M₁
- A black body at a temperature of 227⁰C radiates heat at a rate of 20 cal m⁻²s⁻¹.
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply