| ⇦ | 
| ⇨ |
A particle executes simple harmonic oscillations with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
Options
(a) T/8
(b) T/12
(c) T/2
(d) T/4
Correct Answer:
T/12
Explanation:
Displacement from the mean position y = a sin(2π / T) t
According to the problem y = a/2
a/2 = a sin (2π / T) t
⇒ π / 6 = (2π / T) t ⇒ t = T / 12
This is the minimum time taken by the particle to travel half of the amplitude from the equilibrium position.
Related Questions: - Two planets at mean distances d₁ and d₂ from the sun have their frequencies n₁ and n₂
- In a double slit experiment, the two slits are 1mm apart and the screen is placed 1 m
- Three capacitors each of capacitance C and of breakdown voltage V are joined in series
- If a charge in current of 0.01 A in one coil produces a change in magnetic flux
- A pellet of mass 1 g is moving with an angular velocity of 1 rad/s along a circle
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two planets at mean distances d₁ and d₂ from the sun have their frequencies n₁ and n₂
- In a double slit experiment, the two slits are 1mm apart and the screen is placed 1 m
- Three capacitors each of capacitance C and of breakdown voltage V are joined in series
- If a charge in current of 0.01 A in one coil produces a change in magnetic flux
- A pellet of mass 1 g is moving with an angular velocity of 1 rad/s along a circle
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply