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A particle executes simple harmonic oscillations with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
Options
(a) T/8
(b) T/12
(c) T/2
(d) T/4
Correct Answer:
T/12
Explanation:
Displacement from the mean position y = a sin(2π / T) t
According to the problem y = a/2
a/2 = a sin (2π / T) t
⇒ π / 6 = (2π / T) t ⇒ t = T / 12
This is the minimum time taken by the particle to travel half of the amplitude from the equilibrium position.
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Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A current of 2 A is made to flow through a coil which has only one turn. The magnetic
- Monochromatic light of frequency 6.0 x 10¹⁴ Hz is produced by a laser. The power emitted
- In P-N junction having depletion layer of thickness 10⁻⁶ m, the potential across
- The electric potential at a point in free space due to a charge Q coulomb is Q x 10¹¹ v
- The intermediate image formed by the objective of a compound microscope is
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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