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A particle executes simple harmonic oscillations with an amplitude a. The period of oscillation is T. The minimum time taken by the particle to travel half of the amplitude from the equilibrium position is
Options
(a) T/8
(b) T/12
(c) T/2
(d) T/4
Correct Answer:
T/12
Explanation:
Displacement from the mean position y = a sin(2π / T) t
According to the problem y = a/2
a/2 = a sin (2π / T) t
⇒ π / 6 = (2π / T) t ⇒ t = T / 12
This is the minimum time taken by the particle to travel half of the amplitude from the equilibrium position.
Related Questions: - Which of the following is true for elastic potential energy density?
- The ferromagnetic substance is
- The potential energy of a simple harmonic oscillator when the particle is half way
- At a given temperature the root mean square velocities of oxygen and hydrogen
- The velocity of electromagnetic radiation in a medium of permittivity ε₀
Topics: Oscillations
(58)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which of the following is true for elastic potential energy density?
- The ferromagnetic substance is
- The potential energy of a simple harmonic oscillator when the particle is half way
- At a given temperature the root mean square velocities of oxygen and hydrogen
- The velocity of electromagnetic radiation in a medium of permittivity ε₀
Topics: Oscillations (58)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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